Mathématiques

Question

Salut je suis nulle en maths svp aider moi:Calculer en respectant les priorités et en donnant le résultat sous forme de fraction simplifiée
1) (7/10+5/100)-(8-795/100)
2) 1-(1/6+5/12)
3) 24/15-[2/3-(11/5-2)]
4) 5/12+46/5+66/5+52/13+7/12+53/13+68/5+64/13

1 Réponse

  • Bonjour,


    1) (7/10+5/100)-(8-795/100)

    = [(7 x 10) / (10 x 10) + 5/100] - [(8 x 100) / (1 x 100) - 795/100]

    = (70/100 + 5/100) - (8/100 - 795/100)

    = 75/100 - (- 787/100)

    = 75/100 + 787/100

    = 862/100

    = (2 x 431) / (2 x 50)

    = 431/50


    2) 1-(1/6+5/12)

    = (1 x 12) / (1 x 12) - [(1 x 2) / (6 x 2) + 5/12]

    = 12/12 - (2/12 + 5/12)

    = 12/12 - 7/12

    = 5/12


    3) 24/15-[2/3-(11/5-2)]

    = (24 x 2) / (15 x 2) - [(2 x 10) / (3 x 10) - ((11 x 6) / (5 x 6) - (2 x 30) / (1 x 30)]

    = 48/30 - [20/30 - (66/30 - 60/30)]

    = 48/30 - (20/30 - 6/30)

    = 48/30 - 14/30

    = 34/30

    = (2 x 17) / (2 x 15)

    = 17/15


    4) 5/12+46/5+66/5+52/13+7/12+53/13+68/5+64/13

    = 5/12 + 7/12 + 46/5 + 66/5 + 68/5 + 52/13 + 53/13 + 64/13

    = 58/12 + 186/5 + 119/13

    = (58 x 65) / (12 x 65) + (186 x 156) / (5 x 156) - (119 x 60) / (13 x 60)

    = 3770/780 + 29016/780 - 7140/780

    = 32786/780 - 7140/780

    = 32046/780

    = (6 x 5311) / (6 x 130)

    = 5311/130.

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