Bjr pouvez vous me dire comment on developpe cette expression: (x+2)2-x2-(x+1)2=(x+1)(3-x)

Bonjour,

developpe cette expression:

(x+2)^2-x^2-(x+1)^2=(x+1)(3-x)

x^2 + 4x + 4 - x^2 - x^2 - 2x - 1 = 3x - x^2 + 3 - x

2x^2 - 2x^2 + 2x - 2x + 3 - 3 = 0

0 = 0

Bonjour

x+2)2-x2-(x+1)2=(x+1)(3-x)

X^2 +4x +4 -x^2 -(x^2 + 2x +1) -(x+1)(3-x)=0

4x +4 -x^2 -2x -1 -(3x-x^2+3-x) = 0

-x^2 + 2x + 3 + x^2 -2x-3 = 0

0 = 0