svp aidez moi [tex] \frac{2x + 1}{x - 1} = 3x - 1[/tex] Trouvez x svp

Bonjour

2x+1 = (3x-1)(x-1)

2x+1 -(3x-1)(x-1) = 0

2x +1 -(3x^2 -3x -x+1) = 0

2x +1 -3x^2 + 4x -1 = 0

-3x^2 + 6x = 0

3x (-x+ 2) = 0

3x = 0

X = 0/3 = 0

-x + 2 = 0

-x = -2

X = 2

Bonjour,

Trouver x :

[tex]\dfrac{2x + 1}{x - 1} = 3x - 1[/tex]

Avec [tex]x - 1 \ne 0[/tex]

[tex]x \ne 1[/tex]

[tex]\dfrac{2x + 1}{x - 1} - \dfrac{(3x - 1)(x - 1}{x - 1} = 0[/tex]

2x + 1 - (3x - 1)(x - 1) = 0

2x + 1 - (3x^2 - 3x - x + 1) = 0

2x + 1 - 3x^2 + 4x - 1 = 0

-3x^2 + 6x = 0

3x(-x + 2) = 0

3x = 0 ou - x + 2 = 0

x = 0 ou x = 2