Mathématiques

Question

Bonsoir les Amis, aidez moi svp à réduire les expressions :

A = 5x3V7
B = 5+3V7
C = 2V5 + 3V5
D = 2V5 - 3V5
E = 3V2 x 5V3
F = 3V2 + 5V3
G = 5V7 - 7V7
H = V(3aucarré +2aucarré)
I = V8 - 2V2
J = V8 x (-2V2)
K = (2V5) / V15
L = (8V6) / (2V3)

ce sont des racines; merci !

2 Réponse

  • Bonjour

    A = 5x3V7 = 15V7

    B = 5+3V7 = 5+ 3V7

    C = 2V5 + 3V5 = 5V5

    D = 2V5 - 3V5 = -V5

    E = 3V2 x 5V3 = 10V6

    F = 3V2 + 5V3 = 3V2 + 5V3

    G = 5V7 - 7V7 = -2V7

    H = V(3aucarré +2aucarré)

    = 3+2 = 5

    I = V8 - 2V2 = V4*2 -2V2 = 2V2 -2V2 = 0

    J = V8 x (-2V2) = -2V16 = -2*4 = -8

    K = (2V5) / V15 = 2 /V3

    L = (8V6) / (2V3) = 4V2

  • Bonsoir,

    A = 5x3√7

    A= 15√7

    B = 5+3√7

    B=  5+ 3√7

    C= 2√5 + 3√5

    C= 5√5

    D= 2√5 - 3√5

    D= -√5

    E = 3√2 x 5√3 = 15√6

    F = 3√2 + 5√3

    F= 3√2 + 5√3

    G = 5√7 - 7√7

    G= -2√7

    H =√(3² +2²)

    H= √3²+√2²

    H= 3+2

    H= 5

    I = √8 - 2√2

    I=  √4x√2 -2√2

    I=  2√2 -2√2

    I= 0

    J = √8 (-2√2)

    J= -2√16

    J= -2√4x√4

    J= -2(2)(2)

    J= - 8

    K = (2v5) /√15

    K= 2√5 / √3 x √5

    K = 2 /√3

    L = (8√6) / (2√3)

    L= 8 √3 x √2 / 2√3

    L= 8 √ 2/ 2

    L = 4√2

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