FACTORISER 3x+9x2+12x3 3(x+1)+(x+1)(2X+3) Develloper (3x+2)(x-5)-(4X+1)
Mathématiques
doniaaboubacar2005
Question
FACTORISER
3x+9x2+12x3
3(x+1)+(x+1)(2X+3)
Develloper
(3x+2)(x-5)-(4X+1)
3x+9x2+12x3
3(x+1)+(x+1)(2X+3)
Develloper
(3x+2)(x-5)-(4X+1)
1 Réponse
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1. Réponse arramiyoussra45
3x+9×2+12×3 = 3x+3×3×2+3×4×3 3(x+1)+(x+1)(2X+3)=(x+1)(3+2x+3)
=3(x+(3×2)+(4×3)) =(x+1)(6+2x)
=3(x+6+12) =2(x+1)(3+x)
=3(x+18)
(3x+2)(x-5)-(4X+1)=3x²-15x+2x-10-4x-1
=3x²-17x-11