Bonjour j'aimerai savoir comment on factorise : A = (x+1) (x-4) + (x+3) (x-1) B = (x+1)^2 - (x+3) (x-5) C = (x+3)^2 - (x+1) (x+3) D = (x+4) (x-1) - (x-3) (x+4)
Mathématiques
sanji5602
Question
Bonjour j'aimerai savoir comment on factorise :
A = (x+1) (x-4) + (x+3) (x-1)
B = (x+1)^2 - (x+3) (x-5)
C = (x+3)^2 - (x+1) (x+3)
D = (x+4) (x-1) - (x-3) (x+4)
E = 2x (x+3) +x (x+3) (x+2)
Merci d'avance ☻☻☻
A = (x+1) (x-4) + (x+3) (x-1)
B = (x+1)^2 - (x+3) (x-5)
C = (x+3)^2 - (x+1) (x+3)
D = (x+4) (x-1) - (x-3) (x+4)
E = 2x (x+3) +x (x+3) (x+2)
Merci d'avance ☻☻☻
1 Réponse
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1. Réponse nonotata
Bonjour
C = (x+3)(x+3-x-1)
= (x+3)(2)
= 2(x+3)
D = (x+4)(x-1-x+3)
= (x+4)(2)
= 2(x+4)
E = (x+3)(2x+x^2 +2x)
= (x+3)(x^2+4x)
= x (x+3)(x+4)